Where did you find it? There’s section about absolute maximum ratings, it says
I-in - DC input current - ±5 mA
And it is about input current to the input pin, it is not about supply current.
This would be equivalent of (3.3-1.8)/0.08=18.75 Ohm of real impedance; there’re no such resistor devices in the circuit, two 49.9 in parallel give about 25 Ohms.
Can you put another regulator rated 300 mA (for example)? Looking to other circuits I see they use at least 800 mA regulator; input voltage you feed your regulator with also matters, and its voltage dropout specification also matters.